matlab - Unique combinations of a beaded necklace -



matlab - Unique combinations of a beaded necklace -

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generate possible combinations of elements of vectors (cartesian product) 3 answers

so i'm writing programme determine unique combinations of beaded necklace, can't seem right. rules can't have same necklace forwards , backwards, , can't have same necklace 1 bead beingness slid around other end. i've attached pictures clarify.

i wrote code it, , thought had achieved trying do, it's not working correctly.

n = [1 2 3 4 2 4]; % greenish = 1 % bluish = 2 % yellowish = 3 % reddish = 4 p = perms(n); total = max(size(p)); = 1:max(size(p)) q = p; q(i) = []; j = 1:max(size(q)) if isequal(p(i),fliplr(q(j))) total = total - 1; elseif isequal(p(i),circshift(q(j),[1,1])) total = total - 1; elseif isequal(p(i),circshift(q(j),[length(q(j))-1,length(q(j))-1])) total = total - 1; end disp(total) end end

logically, makes sense me, crazy.

you should p = unique(p,'rows') before loops. see why, phone call perms([1 1 1]) @ command line.

there few issues here:

1) p, perms, 2d matrix, each perm need p(i,:) row. p(i) single number.

2) don't remove wrong answers list, check against them twice. example, first in list [1 2 3 4 2 4]; , sec [4 2 4 3 2 1];. fliplr check compare these 2 combinations twice, 1 time in first loop around, 1 time in second.

3) if want create sure permutation rotation excluded (not moving 1 bead around), you'll need more circshift.

consider using ismember rows alternative 1 time again compare single row (e.g. flipped version of row you're checking) entire matrix.

matlab for-loop unique permutation

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