Behaviour of char pointers in C -



Behaviour of char pointers in C -

i reading string file in next format: n // length of string abcdef // string of length n

like that:

char necklace[400]; fin = fopen("file.in", "r"); fscanf(fin, "%d %s", &n, necklace); char* left = &necklace[0]; char* right = &necklace[n-1];

however, when declare char* before using them, it gives me compilation errors:

char necklace[400]; char* left, right; // causes problem fin = fopen("file.in", "r"); fscanf(fin, "%d %s", &n, necklace); left = &necklace[0]; right = &necklace[n-1];

could please explain me behaviour?

the right way :

char *left,*right;

when do

char *left,right;

then

char *left; char right; /*this not need need *right got right*/

so see compilation errors

c pointers char declaration

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