database - SQL - How to list all tuples in a relation such that tuple 1 is greater than tuple 2 -



database - SQL - How to list all tuples in a relation such that tuple 1 is greater than tuple 2 -

suppose have relation 1 column "value (int)" , values in descending order.

+----------+ + value + +----------+ + 10 + + 9 + + 8 + + 7 + ....

how can list combinations contains 2 tuples such first tuple greater sec tuple

note: may exist 2 tuples same value

the desired outputs should like: (10,9) (10, 8) (9,8), (9,7) (8,7)

you can cross bring together on same table.

select t1.value value1, t2.value value2 thing t1 bring together thing t2 on (t1.value != t2.value , t1.value > t2.value)

sql database

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