linux - How to filter lines with a filter chain -



linux - How to filter lines with a filter chain -

suppose have text file, list.txt, this:

# category 1 foobar # category 2 dummy1 dummy2 dummy3 # category 3 foobar.dummy foobar.dummy

and have bash script, say, list.sh, extract lines list.txt. script takes 1 or more patterns filter text file grep. conceptually, commandline:

cat list.txt | grep filter1 | grep fitler1 | ... | grep filtern

however, problem number of filters varies, have utilize loop filtering. loop, hoping below work.

filters=$* filter in ${filters[@]}; result=`ad_hoc_show $result | grep $filter` done ad_hoc_show $result # should maintain original line construction

for example, below desired output.

$ list.sh foobar foobar foobar.dummy foobar.dummy $ list.sh dummy \d dummy1 dummy2 dummy3

so, advice on how implement ad_hoc_show function?

if grep supports -p can utilize function:

filt() { re=$(printf "(?=.*?%s)" "$@") grep -p "$re" list.txt } filt 'dummy' '\d' dummy1 dummy2 dummy3 filt 'foobar' foobar foobar.dummy foobar.dummy

update: in case grep -p not available can utilize awk:

filt() { re=$(printf "/%s/&&" "$@"); awk "${re:0: -2}" list.txt; } filt 'dummy' '[0-9]' dummy1 dummy2 dummy3 filt 'foobar' foobar foobar.dummy foobar.dummy

linux bash

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