html - How to update a form dropdown menu with PHP? -



html - How to update a form dropdown menu with PHP? -

i have been trying update form's dropdown menu list of entries have in database. database has been created mysql. have been looking solution over, , not sure why, none has worked. latest version have used this:

<head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>untitled document</title> </head> <body> <form method="post" action="submitrequest.php"> staff id: <br> <input type="text" name="stfid" value=""> <br><br> e-mail: <br> <input type="text" name="email" > <br><br> select choice: <br> <select name="choice" value="select" size="1"> <?php $server= '*******'; $user = '*******'; $password = '*******'; $database = '********'; $conn = new mysqli($server, $user, $password, $database); if ($conn->connect_error) { die("connection failed: " . $conn->connect_error); } $sql = "select * choicesgiven"; $result = mysql_query($sql) or die (mysql_error()); while ($row = mysql_fetch_array($result)) { $id=$row["id"]; $titles=$row["ctitle"]; $options.="<option value=\"$id">".$titles; } $conn->close(); ?> <option> <? echo $options ?> </option> </select> <br><br> <input type="submit" name="submit" value="submit"> </form> </body>

i appreciate if help me this, have been trying access around week.

i not sure if improve utilize html file format or create php (if possible @ all), comment or help in advance.

i'm not pro php or html, again, tips / help / assistance appreciated.

update:

thanks @funkdoc , @len_d, however, when used either answers, didn't work. used main php chunk in separate php file, , got error (not sure if it's of use:

fatal error: phone call fellow member function query() on non-object in /home/u309965349/public_html/test2.php on line 11

the code in line 11 is:

$result = $mysqli->query($sql) or die ($mysqli->error);

still searching.....

update 2: used php chunk (the main chunk in middle) , saved php file. when ran it, , echoed $options, got list wanted, when utilize in html document update select part of form, still same $titles, means html syntax not correct.

thank help in advance.

update 3:

to elaborate on above update, utilize php chunk in separate .php file followed:

<?php $server= '*******'; $user = '*******'; $password = '*******'; $database = '********'; $conn = new mysqli($server, $user, $password, $database); $sql = "select * choicesgiven"; $result = $conn->query($sql) or die ($conn->error); $options; while ($row = $result->fetch_object()) { $id=$row->id; $titles=$row->ctitle; // debug_to_console ($id); $options.="<option value='".$id."'>".$titles."</option>"; } echo $options; $conn->close(); ?>

and managed options perfectly. html adding above code html form:

<!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>untitled document</title> </head> <body> <p><span class="error">* required field.</span></p> <form method="post" action="submitrequest.php"> staff id: <br> <input type="text" name="stuid" value=""> <br><br> e-mail: <br> <input type="text" name="email" > <br><br> select choice: <br> <select name="choice" value="select"> <?php $server= '*******'; $user = '*******'; $password = '*******'; $database = '********'; $conn = new mysqli($server, $user, $password, $database); $sql = "select * choicegiven"; $result = $conn->query($sql) or die ($conn->error); $options; while ($row = $result->fetch_object()) { $id=$row->id; $titles=$row->ctitle; // debug_to_console ($id); $options.="<option value='".$id."'>".$titles."</option>"; } } echo $options; $conn->close(); ?> <? echo $options ?> </select> <br><br> <input type="submit" name="submit" value="submit"> </form> </body> </html>

and thing in dropdown menu this: ".$titles."

many , please allow me know if can figure out :)

update 4:

i have tried this:

while ($row = mysql_fetch_array($result)) { $id=$row->id; $titles=$row->btitle; // debug_to_console ($id); echo '<option value="'.$id.'">'.$titles'</option>'; }

you mixing mysqli , mysql commands. edit these lines:

$result = mysql_query($sql) or die (mysql_error()); while ($row = mysql_fetch_array($result))

to:

$result = mysqli_query($conn,$sql); while mysqli_fetch_array($result);

also, alter this:

while ($row = $result->fetch_object())

to this:

while ($row = $result->fetch_array())

php html mysql forms

Comments

Post a Comment

Popular posts from this blog

Delphi change the assembly code of a running process -

Delphi change the assembly code of a running process - i'm trying alter address 00741fa5 has push test.009e721c . alter push test.009e71c8 . procedure callback; asm force $9e71c8 end; procedure tform2.btn1click(sender: tobject); var ppid :dword; pprocess : cardinal; begin getwindowthreadprocessid(findwindow(nil,pchar('test')), @ppid); pprocess := openprocess(process_all_access, false, ppid); injectasm(pprocess, $741fa5, 10, integer(@callback), 0); end; here injectasm function (with error checking) function injectasm(process: longword; injectaddress, injectsize, codeaddress, codesize : integer): pointer; var csize, rsize : integer; replaced : array of byte; jmp : array [0..4] of byte; jmpaddress : integer; nopv : byte; : integer; nbr: ulong_ptr; begin //injectsize must equal or greater 5, because need space our //(far) jmp wwxxyyzz instruction //if there's no space, inject in place of few instructions if injectsize ...
Read more

json - Hibernate and Jackson (java.lang.IllegalStateException: Cannot call sendError() after the response has been committed) -

json - Hibernate and Jackson (java.lang.IllegalStateException: Cannot call sendError() after the response has been committed) - hello have problem hibernate , jackson. have 2 pojos @entity @table(name = "users") public class user implements serializable { static final long serialversionuid = 4235637833262722256l; @id @generatedvalue private int id; @column(name = "creation_date") private date creationdate; @column(name = "first_name") private string firstname; @column(name = "last_name") private string lastname; @version @column(name = "version") private int version; @column(name = "e_mail") private string email; @column(name = "enabled") private boolean enabled; @column(name = "login") private string login; @column(name = "password") private string password; @jsonmanagedreference("role") @onetomany(mappedby = "user", cascade = cascadetype.all,fetch = fetchtyp...
Read more

C++ 11 "class" keyword -

C++ 11 "class" keyword - i've started using c++ 11 little bit more , have few questions on special uses of class keyword. know it's used declare class, there's 2 instances have seen don't understand: method<class t>(); and class class_name *var; why precede typename keyword class in first example, , keyword pointer in sec example? that known elaborated type specifier , necessary when class name "shadowed" or "hidden" , need explicit. class t { }; // love of god don't t t; t t2; if compiler smart, give these warnings: main.cpp:15:5: error: must utilize 'class' tag refer type 't' in scope t t2; ^ class main.cpp:14:7: note: class 't' hidden non-type declaration of 't' here t t; ^ if class not defined, deed forwards declaration. for example: template <typename t> void method() { using type = typename t::value_type; } method...
Read more