python - Printing out csv rows apart from first row -



python - Printing out csv rows apart from first row -

i want read csv file in python, , print out every row apart first row.

i know how print out rows:

with open('myfile.csv', 'rb') csvfile: reader = csv.reader(csvfile, delimiter=',') row in reader: print row

and way can think of not printing out first row is:

with open('myfile.csv', 'rb') csvfile: reader = csv.reader(csvfile, delimiter=',') i, row in enumerate(reader): if != 0: print row

but doesn't seem elegant. other solutions?

csv reader objects iterators, means can skip single entries using next():

with open('myfile.csv', 'rb') csvfile: reader = csv.reader(csvfile, delimiter=',') next(reader) # ignore result row in reader: print row

python csv

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