java - How to choose cssSelector value in Chrome browser using chrome Developer Tool(F12)? -



java - How to choose cssSelector value in Chrome browser using chrome Developer Tool(F12)? -

how take cssselector() chrome browser using chrome developer tools?

can show illustration below code?

webelement searchbox = driver.findelement(by.cssselector("selector")); searchbox.click();

how chose value selector field chrome developer tool?-f12 in chrome. please explain illustration

thanks

if referring selenium tags imply, guess you're trying utilize

driver.findelements(by.classname(".."));

or similar, need familiar css selectors.

for illustration if inspect stackoverflow logo see:

<div id="hlogo"> <a href="/"> stack overflow </a> </div>

so in case use:

driver.findelements(by.id("hlogo"));

or can utilize cssselector doing:

driver.findelements(by.cssselector("#hlogo"));

java javascript selenium-webdriver css-selectors selenium-chromedriver

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